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Euclidean valuation (Definition)

Let $D$ be an integral domain. A Euclidean valuation is a function from the nonzero elements of $D$ to the nonnegative integers $\nu \colon D \setminus \{0_D\} \to \{ x \in \mathbb{Z} : x \ge 0 \}$ such that the following hold:

  • For any $a,b\in D$ with $b\neq 0_D$ , there exist $q,r\in D$ such that $a=bq+r$ with $\nu(r)<\nu(b)$ or $r=0_D$ .
  • For any $a,b\in D \setminus \{0_D\}$ , we have $\nu(a)\leq\nu(ab)$ .

Euclidean valuations are important because they let us define greatest common divisors and use Euclid's algorithm. Some facts about Euclidean valuations include:

  • The minimal value of $\nu$ is $\nu(1_D)$ . That is, $\nu(1_D)\leq\nu(a)$ for any $a\in D \setminus \{0_D\}$ .
  • $u\in D$ is a unit if and only if $\nu(u)=\nu(1_D)$ .
  • For any $a\in D \setminus \{0_D\}$ and any unit $u$ of $D$ , we have $\nu(a)=\nu(au)$ .

These facts can be proven as follows:

  • If $a\in D \setminus \{0_D\}$ , then$$ \nu(1_D)\leq\nu(1_D\cdot a)=\nu(a).$$
  • If $u\in D$ is a unit, then let $v\in D$ be its inverse. Thus,$$ \nu(1_D)\leq\nu(u)\leq\nu(uv)=\nu(1_D).$$ Conversely, if $\nu(u)=\nu(1_D)$ , then there exist $q,r\in D$ with $\nu(r)<\nu(u)=\nu(1_D)$ or $r=0_D$ such that$$ 1_D=qu+r.$$ Since $\nu(r)<\nu(1_D)$ is impossible, we must have $r=0_D$ . Hence, $q$ is the inverse of $u$ .
  • Let $v\in D$ be the inverse of $u$ . Then$$ \nu(a)\leq\nu(au)\leq\nu(auv)=\nu(a).$$

Note that an integral domain is a Euclidean domain if and only if it has a Euclidean valuation.

Below are some examples of Euclidean domains and their Euclidean valuations:

  • Any field $F$ is a Euclidean domain under the Euclidean valuation $\nu(a)=0$ for all $a\in F \setminus \{0_F\}$ .
  • $\mathbb{Z}$ is a Euclidean domain with absolute value acting as its Euclidean valuation.
  • If $F$ is a field, then $F[x]$ , the ring of polynomials over $F$ , is a Euclidean domain with degree acting as its Euclidean valuation: If $n$ is a nonnegative integer and $a_0,\dots,a_n\in F$ with $a_n\neq 0_F$ , then$$ \nu\left(\sum_{j=0}^n a_jx^j\right)=n.$$

Due to the fact that the ring of polynomials over any field is always a Euclidean domain with degree acting as its Euclidean valuation, some refer to a Euclidean valuation as a degree function. This is done, for example, in Joseph J. Rotman's A First Course in Abstract Algebra.




"Euclidean valuation" is owned by Wkbj79. [ full author list (3) | owner history (2) ]
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See Also: PID, UFD, ring, integral domain, Euclidean domain, proof that a Euclidean domain is a PID, Dedekind-Hasse valuation, norm-Euclidean number field

Other names:  degree function

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norm-Euclidean number field (Topic) by pahio
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Cross-references: degree, polynomials, ring, absolute value, field, Euclidean domain, conversely, unit, Euclid's algorithm, greatest common divisors, integers, function, integral domain
There are 9 references to this entry.

This is version 12 of Euclidean valuation, born on 2002-05-27, modified 2009-03-20.
Object id is 2956, canonical name is EuclideanValuation.
Accessed 13280 times total.

Classification:
AMS MSC13F07 (Commutative rings and algebras :: Arithmetic rings and other special rings :: Euclidean rings and generalizations)

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