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$\Diamond$ (Definition)
Definition 1   Let $ S\subseteq\kappa$ be a stationary set. Then the combinatorial principle $ \Diamond_S$ holds if and only if there is a sequence $ \langle A_{\alpha}\rangle_{\alpha\in S}$ such that each $ A_{\alpha}\subseteq\alpha$ and for any $ A\subseteq\kappa$, $ \{\alpha\in S\mid A\cap\alpha=A_{\alpha}\}$ is stationary.

To get some sense of what this means, observe that for any $ \lambda<\kappa$, $ \{\lambda\}\subseteq\kappa$, so the set of $ A_\alpha=\{\lambda\}$ is stationary (in $ \kappa$). More strongly, suppose $ \kappa>\lambda$. Then any subset of $ T\subset\lambda$ is bounded in $ \kappa$ so $ A_\alpha=T$ on a stationary set. Since $ \vert S\vert=\kappa$, it follows that $ 2^\lambda\leq\kappa$. Hence $ \Diamond_{\aleph_1}$, the most common form (often written as just $ \Diamond$), implies CH.

C. Akemann and N. Weaver used $ \Diamond$ to construct a $ C^*$-algebra serving as a counterexample to Naimark's problem.

Bibliography

1
Akemann, C., and N. Weaver, Consistency of a counterexample to Naimark's problem. Preprint available on the arXiv at http://arxiv.org/abs/math.OA/0312135.



"$\Diamond$" is owned by Henry. [ full author list (2) | owner history (2) ]
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See Also: $\clubsuit$, $\Diamond$ is equivalent to $\clubsuit$ and continuum hypothesis, proof of $\Diamond$ is equivalent to $\clubsuit$ and continuum hypothesis, combinatorial principle

Other names:  diamond
Also defines:  $\Diamond_S$
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Cross-references: counterexample, CH, implies, bounded, subset, stationary, sequence, combinatorial principle, stationary set
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This is version 5 of $\Diamond$, born on 2002-07-31, modified 2004-04-10.
Object id is 3245, canonical name is Diamond.
Accessed 4281 times total.

Classification:
AMS MSC03E65 (Mathematical logic and foundations :: Set theory :: Other hypotheses and axioms)

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