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Euler product (Definition)

If $ f$ is a multiplicative function, then

$\displaystyle \sum_{n=1}^\infty f(n)= \prod_{p\text{ is prime}}(1+f(p)+f(p^2)+\dotsb)$ (1)

provided the sum on the left converges absolutely. The product on the right is called the Euler product for the sum on the left.
Proof. [Proof of (1)] Expand partial products on right of (1) to obtain by fundamental theorem of arithmetic
$\displaystyle \prod_{p<y}(1+f(p)+f(p^2)+\dotsb)$ $\displaystyle = \sum_{k_1}f(p_1^{k_1})\sum_{k_2}f(p_2^{k_2}) \dotsb\sum_{k_t}f(p_t^{k_t})$    
  $\displaystyle =\sum_{k_1,k_2,\dotsc,k_t} f(p_1^{k_1})f(p_2^{k_2})\dotsb f(p_t^{k_t})$    
  $\displaystyle =\sum_{k_1,k_2,\dotsc,k_t} f(p_1^{k_1}p_2^{k_2}\dotsb p_t^{k_t})$    
  $\displaystyle =\sum_{P_+(n)<y} f(n)$    

where $ p_1,p_2,\dotsc,p_t$ are all the primes between $ 1$ and $ y$, and $ P_+(n)$ denotes the largest prime factor of $ n$. Since every natural number less than $ y$ has no factors exceeding $ y$ we have that
$\displaystyle \left\lvert \sum_{n=1}^\infty f(n)-\sum_{P_+(n)<y} f(n)\right\rvert \leq\sum_{n=y}^\infty \left\lvert f(n)\right\rvert$    

which tends to zero as $ y\to \infty$. $ \qedsymbol$

Examples



"Euler product" is owned by bbukh.
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See Also: multiplicative function, Riemann zeta function

Keywords:  infinitude of primes
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Cross-references: proof of infinitude of primes, rational functions, irrational number, series, Riemann zeta function, consequences, estimate, function, factors, natural number, prime factor, primes, fundamental theorem of arithmetic, expand, right, product, converges absolutely, sum, multiplicative function
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This is version 5 of Euler product, born on 2004-02-21, modified 2004-02-22.
Object id is 5609, canonical name is EulerProduct.
Accessed 5001 times total.

Classification:
AMS MSC11A05 (Number theory :: Elementary number theory :: Multiplicative structure; Euclidean algorithm; greatest common divisors)
 11A51 (Number theory :: Elementary number theory :: Factorization; primality)

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about proving the infinitude of primes from the Euler product by saforres on 2004-06-21 20:28:58
You mention how at $s=2$, the fact that the product of all primes yields an irrational number is a proof of the infinitude of primes.

That's true, but there's an easier way to get this result from the Euler product, which doesn't depend on comparatively advanced results like the irrationality of $\Pi$:

The $s=1$ case corresponds to the harmonic series. Proving that this diverges is a standard exercise which students will be familiar with. If there were only finitely many primes, the Euler product would be a nonzero rational number and so the harmonic series would have to converge.
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