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[parent] extremum points of function of several variables (Theorem)

The points where a function of two or more real variables attains its extremum values are found in the set containing the points where all first order partial derivatives vanish, the points where one or more of those derivatives does not exist, and the points where the function itself is discontinuous.

Example 1. The function $ f(x,\,y) = x^2\!+\!y^2\!+\!1$ from $ \mathbb{R}^2$ to $ \mathbb{R}$ has a (global) minimum point $ (0,\,0)$, where its partial derivatives $ \frac{\partial f}{\partial x} = 2x$ and $ \frac{\partial f}{\partial y} = 2y$ both equal to zero.

Example 2. Also the function $ g(x,\,y) = \sqrt{x^2\!+\!y^2}$ from $ \mathbb{R}^2$ to $ \mathbb{R}$ has a (global) minimum in $ (0,\,0)$, where neither of its partial derivatives $ \frac{\partial g}{\partial x}$ and $ \frac{\partial g}{\partial y}$ exist.

Example 3. The function $ f(x,\,y,\,z)= x^2\!+\!y^2\!+\!z^2$ from $ \mathbb{R}^3$ to $ \mathbb{R}$ has an absolute minimum point $ (0,\,0,\,0)$, since $ \nabla{f}=2x\mathbf{i}\!+\!2y\mathbf{j}\!+\!2z\mathbf{k}=\mathbf{0}\,\implies\,x=y=z=0$, $ \frac{\partial^2{f}}{\partial{x}^2}=\frac{\partial^2{f}}{\partial{y}^2}=\frac{\partial^2{f}}{\partial{z}^2}=2>0$, and $ f(0,\,0,\,0)\leq f(x,\,y,\,z)$ for all $ (x,\,y,\,z)\,\in\mathbb{R}^3$.



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Cross-references: discontinuous, derivatives, vanish, partial derivatives, first order, extremum, variables, real, function, points
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This is version 9 of extremum points of function of several variables, born on 2007-07-15, modified 2008-09-22.
Object id is 9769, canonical name is ExtremumPointsOfFunctionOfSeveralVariables.
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AMS MSC26B12 (Real functions :: Functions of several variables :: Calculus of vector functions)

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