PlanetMath (more info)
 Math for the people, by the people.
Encyclopedia | Requests | Forums | Docs | Wiki | Random | RSS  
Login
create new user
name:
pass:
forget your password?
Main Menu
Owner confidence rating: Very high Entry average rating: No information on entry rating
[parent] group scheme of multiplicative units (Example)

Let $ R=\mathbb{Z}[X,Y]/\left<XY-1\right>$. Then $ {\mathrm{Spec}}R$ is an affine scheme. The natural homomorphism $ \mathbb{Z}\to R$ makes $ R$ into a scheme over $ {\mathrm{Spec}}\mathbb{Z}$, i.e. a $ \mathbb{Z}$-scheme.

What are the $ \mathbb{Z}$-points of $ {\mathrm{Spec}}R$? Recall that an $ S$-point of a scheme $ X$ is a morphism $ S\to X$; if we are working in the category of schemes over $ Y$, then the morphism is expected to commute with the structure morphisms. So, here, we seek homomorphisms $ \mathbb{Z}[X,Y]/\left<XY-1\right> \to \mathbb{Z}$. Such a homomorphism must take $ X$ to an invertible element, and it must take $ Y$ to its inverse. Therefore there are two, one taking $ X$ to $ 1$ and one taking $ X$ to $ -1$. One recognizes these as the multiplicative units of $ \mathbb{Z}$, and indeed if $ S$ is any ring, then the $ S$-points of $ {\mathrm{Spec}}R$ are exactly the multiplicative units of $ S$. For this reason, this scheme is often denoted $ \mathbb{G}_m$. It is an example of a group scheme.

We can regard any morphism as a family of schemes, one for each fibre. Since we have a morphism $ \mathbb{G}_m \to \mathbb{Z}$, we can ask about the fibres of this morphism. If we select a point $ x$ of $ {\mathrm{Spec}}\mathbb{Z}$, we have two choices. Such a point must be a prime ideal of $ \mathbb{Z}$, and there are two kinds: ideals generated by a prime number, and the zero ideal. If we select a point $ x$ with residue field $ k(x)$, then the fiber of this morphism will be $ {\mathrm{Spec}}R \times {\mathrm{Spec}}k(x)$, which is the same as $ {\mathrm{Spec}}R\otimes k(x)$. But looking at the definition of $ R$, we see that this is $ {\mathrm{Spec}}k(x)[X,Y]/\left<XY-1\right>$, which is just the scheme whose points are the nonzero elements of $ k(x)$.

In other words, we have a family of schemes, one in each characteristic. Of course, normally one wants a family to have some additional sort of smoothness condition, but this demonstrates that it is quite possible to have a family of schemes in different characteristics; sometimes one can deduce the behaviour in one characteristic from the behaviour in another. This approach can be useful, for example, when dealing with Hilbert modular varieties.



"group scheme of multiplicative units" is owned by mathcam. [ full author list (2) | owner history (1) ]
(view preamble)

View style:

See Also: group scheme

Other names:  $\mathbb{G}_m$
Also defines:  group scheme of multiplicative units

This object's parent.
Log in to rate this entry.
(view current ratings)

Cross-references: varieties, modular, characteristic, residue field, zero ideal, prime number, ideal generated bies, prime ideal, point, fibre, group scheme, ring, units, multiplicative, inverse, invertible, structure morphisms, category, morphism, scheme, natural homomorphism, affine scheme
There is 1 reference to this entry.

This is version 4 of group scheme of multiplicative units, born on 2004-02-11, modified 2005-03-25.
Object id is 5567, canonical name is GroupSchemeOfMultiplicativeUnits.
Accessed 3207 times total.

Classification:
AMS MSC14A15 (Algebraic geometry :: Foundations :: Schemes and morphisms)

Pending Errata and Addenda
None.
[ View all 1 ]
Discussion
Style: Expand: Order:
forum policy

No messages.

Interact
post | correct | update request | add example | add (any)