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[parent] modular function (Definition)

Let $ G$ be a locally compact Hausdorff topological group and $ \mu$ a left Haar measure. Although left and right Haar measures in $ G$ always exist, they generally do not coincide, i.e. a left Haar measure is usually not invariant under right translations. Nevertheless, the right translations of a left Haar measure can be easily described as explained in the following theorem.

$ \,$

Theorem - Let $ G$ be a locally compact Hausdorff topological group and $ \mu$ a left Haar measure in $ G$. Then, there exists a continuous homomorphism $ \Delta:G \longrightarrow \mathbb{R}^+$ such that, for every $ t \in G$ and every measurable subset $ A$

$\displaystyle \mu(At) = \Delta(t^{-1})\mu(A) $
Moreover, if $ f:G \longrightarrow \mathbb{C}$ is an integrable function then
$\displaystyle \Delta(t)\int_Gf(st) \mu(s) = \int_G f(s) \mu(s) $

$ \,$

The function $ \Delta$ is called the modular function of $ G$ (notice that, by uniqueness up to scalar multiple of left Haar measures, $ \Delta$ only depends on $ G$). Other names for $ \Delta$ that can be found are: Haar modulus, or modular character or modular homomorphism.

We now prove the above theorem, except the continuity of $ \Delta$ (which is slightly harder to obtain).

$ \,$

Proof (except continuity of $ \Delta$):

Let $ t \in G$. The function $ \nu$, defined on measurable subsets $ A$ by

$\displaystyle \nu (A):= \mu(At) $

is easily seen to be a measure in $ G$. Moreover, $ \nu$ is left invariant (since $ \mu$ is left invariant) and satisfies the additional conditions to be a left Haar measure. By the uniqueness of left Haar measures, $ \mu$ must be a multiple of $ \nu$, i.e. $ \mu=\Delta(t)\nu$ for some positive scalar $ \Delta(t) \in \mathbb{R}^+$. Thus, we have proven that for every measurable subset $ A$

$\displaystyle \mu(At)= \Delta(t)^{-1}\mu(A) $

Now for $ s, t \in G$ we have that $ \mu(Ast)=\Delta(st)^{-1}\mu(A)$, but also

  • $ \mu(Ast)= \Delta(t)^{-1}\mu(As)$, and
  • $ \mu(As) = \Delta(s)^{-1}\mu(A)$
So, we can see that, for every measurable subset $ A$,

$\displaystyle \Delta(st)^{-1}\mu(A) = \Delta(t)^{-1}\Delta(s)^{-1}\mu(A) $
Hence, $ \Delta(st) = \Delta(s)\Delta(t)$. Thus, $ \Delta$ is an homomorphism.

The statement about integrals of functions follows easily by approximation by simple functions. For simple functions it is easy to see it is true using the now established condition $ \mu(At) = \Delta(t^{-1})\mu(A)$. $ \square$



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Other names:  Haar modulus, modular character, modular homomorphism

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Cross-references: easy to see, simple functions, approximation, integrals, scalar, positive, multiple, measure, scalar multiple, function, subset, measurable, homomorphism, continuous, translations, right, invariant, right Haar measures, left Haar measure, topological group, Hausdorff, locally compact
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This is version 5 of modular function, born on 2008-04-04, modified 2008-04-08.
Object id is 10479, canonical name is ModularFunction.
Accessed 364 times total.

Classification:
AMS MSC22D05 (Topological groups, Lie groups :: Locally compact groups and their algebras :: General properties and structure of locally compact groups)
 28C10 (Measure and integration :: Set functions and measures on spaces with additional structure :: Set functions and measures on topological groups, Haar measures, invariant measures)

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