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theorem on constructible numbers
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(Theorem)
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Before proving this theorem, some preliminaries must be addressed.
First of all, within this entry, the following nonconventional definition will be used:
Let be a subset of
that contains a nonzero complex number and
. Then is immediately constructible from if any of the following hold:
-
for some ;
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for some ;
for some ;
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for some with ;
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for some with and
with
.
The following lemmas are clear from this definition:
Lemma 1 Let be a subset of
that contains a nonzero complex number and
. Then is constructible from if and only if there exists a finite sequence
such that is immediately constructible from , is immediately constructible from
, , and is immediately constructible from
.
Lemma 2 Let be a subfield of
and
. If is immediately constructible from , then either
or
.
Now to prove the theorem.
Proof. By the first lemma, there exists a finite sequence
 such that  is immediately constructible from
 ,  is immediately constructible from
 ,  , and  is immediately constructible from
 . Thus,  is immediately constructible from
 ,  , and  is immediately constructible from
 . By the second lemma,
![% latex2html id marker 520 $ [\mathbb{Q}(\alpha_1)\!:\!\mathbb{Q}]$ % latex2html id marker 520 $ [\mathbb{Q}(\alpha_1)\!:\!\mathbb{Q}]$](http://images.planetmath.org:8080/cache/objects/9614/l2h/img58.png) is equal to either  or  ,
![% latex2html id marker 526 $ [\mathbb{Q}(\alpha_1,\alpha_2)\!:\!\mathbb{Q}(\alpha_1)]$ % latex2html id marker 526 $ [\mathbb{Q}(\alpha_1,\alpha_2)\!:\!\mathbb{Q}(\alpha_1)]$](http://images.planetmath.org:8080/cache/objects/9614/l2h/img61.png) is equal to either  or  ,  , and
![% latex2html id marker 534 $ [\mathbb{Q}(\alpha_1, \dots ,\alpha_n,\alpha)\!:\!\mathbb{Q}(\alpha_1, \dots ,\alpha_n)]$ % latex2html id marker 534 $ [\mathbb{Q}(\alpha_1, \dots ,\alpha_n,\alpha)\!:\!\mathbb{Q}(\alpha_1, \dots ,\alpha_n)]$](http://images.planetmath.org:8080/cache/objects/9614/l2h/img65.png) is equal to either  or  . Therefore, there exists a nonnegative integer  such that
![% latex2html id marker 542 $ [\mathbb{Q}(\alpha_1, \dots ,\alpha_n,\alpha)\!:\!\mathbb{Q}]=2^m$ % latex2html id marker 542 $ [\mathbb{Q}(\alpha_1, \dots ,\alpha_n,\alpha)\!:\!\mathbb{Q}]=2^m$](http://images.planetmath.org:8080/cache/objects/9614/l2h/img69.png) . Since
 , it follows that there exists a nonnegative integer  such that
![% latex2html id marker 548 $ [\mathbb{Q}(\alpha)\!:\!\mathbb{Q}]=2^k$ % latex2html id marker 548 $ [\mathbb{Q}(\alpha)\!:\!\mathbb{Q}]=2^k$](http://images.planetmath.org:8080/cache/objects/9614/l2h/img72.png) . 
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"theorem on constructible numbers" is owned by Wkbj79.
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(view preamble)
Cross-references: subfield, finite sequence, constructible from, clear, complex number, contains, subset, integer, field of constructible numbers
There are 3 references to this entry.
This is version 7 of theorem on constructible numbers, born on 2007-06-18, modified 2007-06-23.
Object id is 9614, canonical name is TheoremOnConstructibleNumbers.
Accessed 693 times total.
Classification:
| AMS MSC: | 12D15 (Field theory and polynomials :: Real and complex fields :: Fields related with sums of squares ) |
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Pending Errata and Addenda
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