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inverse image (Definition)

Let $ f: A \longrightarrow B$ be a function, and let $ U \subset B$ be a subset. The inverse image of $ U$ is the set $ f^{-1}(U) \subset A$ consisting of all elements $ a \in A$ such that $ f(a) \in U$.

The inverse image commutes with all set operations: For any collection $ \{U_i\}_{i \in I}$ of subsets of $ B$, we have the following identities for

  1. Unions:
    $\displaystyle f^{-1}\left(\bigcup_{i \in I} U_i\right) = \bigcup_{i \in I} f^{-1}(U_i)$
  2. Intersections:
    $\displaystyle f^{-1}\left(\bigcap_{i \in I} U_i\right) = \bigcap_{i \in I} f^{-1}(U_i)$
and for any subsets $ U$ and $ V$ of $ B$, we have identities for
  1. Complements:
    $\displaystyle \left(f^{-1}(U)\right)^\complement = f^{-1}(U^\complement)$
  2. Set differences:
    $\displaystyle f^{-1}(U \setminus V) = f^{-1}(U) \setminus f^{-1}(V)$
  3. Symmetric differences:
    $\displaystyle f^{-1}(U \bigtriangleup V) = f^{-1}(U) \bigtriangleup f^{-1}(V)$
In addition, for $ X \subset A$ and $ Y \subset B$, the inverse image satisfies the miscellaneous identities
  1. $ (f\vert _X)^{-1}(Y)=X\cap f^{-1}(Y)$
  2. $ f\left(f^{-1}(Y)\right) = Y\cap f(A)$
  3. $ X \subset f^{-1}(f(X))$, with equality if $ f$ is injective.



"inverse image" is owned by djao. [ full author list (2) | owner history (1) ]
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See Also: mapping, direct image

Other names:  preimage

Attachments:
the inverse image commutes with set operations (Proof) by matte
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Cross-references: injective, equality, satisfies, symmetric differences, set differences, complements, intersections, unions, identities, collection, operations, subset, function
There are 44 references to this entry.

This is version 5 of inverse image, born on 2001-10-21, modified 2003-07-30.
Object id is 442, canonical name is InverseImage.
Accessed 12412 times total.

Classification:
AMS MSC03E20 (Mathematical logic and foundations :: Set theory :: Other classical set theory )

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