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[parent] Jacobi's theorem (Theorem)

Jacobi's Theorem Any skew-symmetric matrix of odd order has determinant equal to 0.

Proof. Suppose $ A$ is an $ n\times n$ square matrix. For the determinant, we then have $ \det A = \det A^T$, and $ \det (-A) = (-1)^n \det A$. Thus, since $ n$ is odd, and $ A^T=-A$, we have $ \det A = -\det A$, and the theorem follows. $ \Box$

Remarks

  1. According to [1], this theorem was given by Carl Gustav Jacob Jacobi (1804-1851) [2] in 1827.
  2. The $ 2\times 2$ matrix $ \left( \begin{array}{cc} 0 & 1 \ -1 & 0 \end{array} \right)$ shows that Jacobi's theorem does not hold for $ 2\times 2$ matrices. The determinant of the $ 2n\times 2n$ block matrix with these $ 2\times 2$ matrices on the diagonal equals $ (-1)^n$. Thus Jacobi's theorem does not hold for matrices of even order.
  3. For $ n=3$, any antisymmetric matrix $ A$ can be written as
    $\displaystyle A = \begin{pmatrix} 0 & -v_3 & v_2 \ v_3 & 0 & -v_1 \ -v_2 & v_1 & 0 \end{pmatrix}$
    for some real $ v_1,v_2,v_3$, which can be written as a vector $ v=(v_1,v_2,v_3)$. Then $ A$ is the matrix representing the mapping $ u\mapsto v\times u$, that is, the cross product with respect to $ v$. Since $ Av=v\times v=0$, we have $ \det A=0$.

Bibliography

1
H. Eves, Elementary Matrix Theory, Dover publications, 1980.
2
The MacTutor History of Mathematics archive, Carl Gustav Jacob Jacobi



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Cross-references: cross product, mapping, vector, real, antisymmetric, even, diagonal, block matrix, matrix, Carl Gustav Jacob Jacobi, square matrix, determinant, order, odd, skew-symmetric matrix
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This is version 10 of Jacobi's theorem, born on 2003-04-05, modified 2006-09-13.
Object id is 4156, canonical name is JacobisTheorem.
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Classification:
AMS MSC15-00 (Linear and multilinear algebra; matrix theory :: General reference works )

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