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[parent] left / right perpendicular (Derivation)

Given a sesquilinear form $ b:V\times V\rightarrow k$ over the field $ k$, if $ v,u\in V$ such that $ b(v,u)=0$ then we say $ v$ is right perpendicular to $ u$ and denote it $ v\bot u$. Likewise $ u$ is left perpendicular to $ v$ and can be denoted by $ u\top v$.

By definition $ v\perp u$ if and only if $ u\top v$. However, $ v\perp u$ need not imply $ u\perp v$.

For example, let $ V=k\oplus k$ and $ b( (v_1,v_2), (u_1,u_2))=v_1 u_2$. Then $ b((0,1),(1,0))=0$ so $ (0,1)\bot (1,0)$, or equivalently, $ (1,0)\top (0,1)$. However $ b((1,0),(0,1))=1\neq 0$ so $ (1,0)$ is not right perpendicular to $ (0,1)$ and $ (0,1)$ is not left perpendicular to $ (1,0)$.



"left / right perpendicular" is owned by Algeboy.
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Also defines:  left perpendicular, right perpendicular
Keywords:  perpendicular

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Cross-references: imply, definition, field, sesquilinear form
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This is version 4 of left / right perpendicular, born on 2006-09-06, modified 2006-09-07.
Object id is 8315, canonical name is LeftRightPerpendicular.
Accessed 1380 times total.

Classification:
AMS MSC15A63 (Linear and multilinear algebra; matrix theory :: Quadratic and bilinear forms, inner products)

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