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[parent] median of trapezoid (Theorem)

The segment connecting the midpoints of the legs of a trapezoid, i.e. the median of the trapezoid, is parallel to the bases and its length equals the arithmetic mean of the legs.

Proof. Let $ AB$ and $ CD$ be the bases of a trapezoid $ ABCD$ and $ E$ the midpoint of the leg $ AD$ and $ F$ the midpoint of the leg $ BC$. Then the median $ EF$ may be determined as vector as follows:

$\displaystyle \overrightarrow{EF}$ $\displaystyle = \overrightarrow{ED}+\overrightarrow{DC}+\overrightarrow{CF}$    
  $\displaystyle = \frac{1}{2}\overrightarrow{AD}+\overrightarrow{DC}+\frac{1}{2}\overrightarrow{CB}$    
  $\displaystyle = \frac{1}{2}(\overrightarrow{AD}+\overrightarrow{DC}+\overrightarrow{CB})+\frac{1}{2}\overrightarrow{DC}$    
  $\displaystyle = \frac{1}{2}\overrightarrow{AB}+\frac{1}{2}\overrightarrow{DC}$    
  $\displaystyle = \frac{1}{2}(\overrightarrow{AB}+\overrightarrow{DC})$    

The last expression tells that $ \overrightarrow{EF} \parallel \overrightarrow{AB}+\overrightarrow{DC} \parallel \overrightarrow{AB}$ and $ \displaystyle\vert\overrightarrow{EF}\vert = \frac{\vert\overrightarrow{AB}\!+... ...{2} = \frac{\vert\overrightarrow{AB}\vert\!+\!\vert\overrightarrow{DC}\vert}{2}$. Q.E.D.

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See Also: mutual positions of vectors, mid-segment theorem, triangle mid-segment theorem


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Cross-references: expression, vector, leg, arithmetic mean, length, bases, parallel, median, trapezoid, midpoints, segment
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This is version 3 of median of trapezoid, born on 2008-02-05, modified 2008-05-23.
Object id is 10237, canonical name is MedianOfTrapezoid.
Accessed 563 times total.

Classification:
AMS MSC51M04 (Geometry :: Real and complex geometry :: Elementary problems in Euclidean geometries)
 51M25 (Geometry :: Real and complex geometry :: Length, area and volume)

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