From Wikipedia

The Moscow Mathematical Papyrus is also called the Golenischev Mathematical Papyrus, after its first owner, Egyptologist Vladimir Goleniščev. It later entered the collection of the Pushkin State Museum of Fine Arts in Moscow, where it remains today. Based on the palaeography of the hieratic text, it probably dates to the Eleventh dynasty of Egypt. Approximately 18 feet long and varying between 1 1/2 and 3 inches wide, its format was divided into 25 problems with solutions by the Soviet Orientalist Vasily Vasilievich Struve[1] in 1930.[2] It is one of the two well-known Mathematical Papyri along with the Rhind Mathematical Papyrus. The Moscow Mathematical Papyrus is older than the Rhind Mathematical Papyrus, while the latter is the larger of the two. [3] Contents [hide]

* 1 Problem 14: Volume of frustum of square pyramid * 2 See also * 3 References o 3.1 Full Text of the Moscow Mathematical Papyrus o 3.2 Other references * 4 Footnotes

[edit] Problem 14: Volume of frustum of square pyramid

The 14th problem of the Moscow Mathematical Papyrus is the most difficult problem. It calculates the volume of a frustum. This is the only ancient example finding the volume of a frustum of a pyramid or cone[4 There are no known examples of a volume calculation of a complete pyramid or cone. Similarly, in Mesopotamia interest seems to have been in finding the volumes of frusta rather than complete pyramids or cones. The Babylonian mathematical tablet BM 85194, for example, sets out the calculation for the volume of a trapezium-sectioned fortification wall.

Problem 14 states that a pyramid has been truncated in such a way that the top area is a square of length 2 units, the bottom a square of length 4 units, and the height 6 units, as shown. The volume is found to be 56 cubic units, which is correct.

Image:Pyramid frustum for Moscow papyrus 14.jpg

The text of the example runs like this: "If you are told: a truncated pyramid of 6 for the vertical height by 4 on the base by 2 on the top: You are to square the 4; result 16. You are to double 4; result 8. You are to square this 2; result 4. You are to add the 16 and the 8 and the 4; result 28. You are to take 1/3 of 6; result 2. You are to take 28 twice; result 56. See, it is of 56. You will find (it) right" [5]

This describes the correct calculation:

which indicates that the Egyptians knew the correct formula for obtaining the volume of a truncated pyramid:

We do not know how the Egyptians arrived at the formula for the volume of a frustum. The Babylonians had taken the incorrect approach of averaging the area of base and top and multiplying by height.[6]

Touraeff, the first commentator, strangely saw Problem 14 as describing the more general formula for the volume of any frustum[7], a formula that was not derived for another 3000 years. He was not alone in this view.[8]

Other area and volume problems from the Middle Kingdom are found in the Rhind Mathematical Papyrus.