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number of (nondistinct) prime factors function (Definition)

The number of (nondistinct) prime factors function $ \Omega(n)$ counts with repetition how many prime factors a natural number $ n$ has. If $ \displaystyle n= \prod_{j= 1}^k {p_j}^{a_j}$ where the $ k$ primes $ p_j$ are distinct and the $ a_j$ are natural numbers, then $ \displaystyle \Omega(n)=\sum_{j=1}^k a_j$.

Note that, if $ n$ is a squarefree number, then $ \omega(n)=\Omega(n)$, where $ \omega(n)$ is the number of distinct prime factors function. Otherwise, $ \omega(n)<\Omega(n)$.

Note also that $ \Omega(n)$ is a completely additive function and thus can be exponentiated to define a completely multiplicative function. For example, the Liouville function can be defined as $ \lambda(n) = (-1)^{\Omega(n)}$.

The sequence $ \{\Omega(n)\}$ appears in the OEIS as sequence A001222.

The sequence $ \{2^{\Omega(n)}\}$ appears in the OEIS as sequence A061142.



"number of (nondistinct) prime factors function" is owned by Wkbj79.
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See Also: number of distinct prime factors function, $2^{\omega(n)} \le \tau(n) \le 2^{\Omega(n)}$


Attachments:
$\displaystyle \sum_{n \le x} y^{\Omega(n)}=O\left( \frac{x(\log x)^{y-1}}{2-y} \right)$ for $1 \le y<2$ (Theorem) by Wkbj79
$\displaystyle x\log^2x=O\left(\sum_{n \le x} 2^{\Omega(n)} \right)$ (Theorem) by Wkbj79
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Cross-references: OEIS, sequence, Liouville function, completely multiplicative function, completely additive function, number of distinct prime factors function, number, squarefree, primes, natural number, prime factors
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This is version 13 of number of (nondistinct) prime factors function, born on 2006-07-27, modified 2007-04-15.
Object id is 8183, canonical name is NumberOfNondistinctPrimeFactorsFunction.
Accessed 1256 times total.

Classification:
AMS MSC11A25 (Number theory :: Elementary number theory :: Arithmetic functions; related numbers; inversion formulas)

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