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[parent] opposing angles in a cyclic quadrilateral are supplementary (Theorem)
Theorem 1   [Euclid, Book III, Prop. 22] If a quadrilateral is inscribed in a circle, then opposite angles of the quadrilateral sum to $ 180^{\circ}$.
Proof. Let $ ABCD$ be a quadrilateral inscribed in a circle

\begin{pspicture*}(-3.0000,-3.0000)(3.0000,3.0000) \rput(-3.1,-3.1){.} \rput(3.1... ...0,0.0000)(0.5176,1.9319) \psline(0.0000,0.0000)(1.5321,-1.2856) \end{pspicture*}
Note that $ \angle BAD$ subtends arc $ BCD$ and $ \angle BCD$ subtends arc $ BAD$. Now, since a circumferential angle is half the corresponding central angle, we see that $ \angle BAD + \angle BCD$ is one half of the sum of the two angles $ BOD$ at $ O$. But the sum of these two angles is $ 360^{\circ}$, so that
$\displaystyle \angle BAD + \angle BCD = 180^{\circ}$
Similarly, the sum of the other two opposing angles is also $ 180^{\circ}$. $ \qedsymbol$



"opposing angles in a cyclic quadrilateral are supplementary" is owned by rm50.
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Cross-references: circumferential angle is half the corresponding central angle, arc, sum, angles, opposite, circle, inscribed, quadrilateral
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This is version 5 of opposing angles in a cyclic quadrilateral are supplementary, born on 2007-06-07, modified 2007-07-27.
Object id is 9552, canonical name is OpposingAnglesInACyclicQuadrilateralAreSupplementary.
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AMS MSC51M04 (Geometry :: Real and complex geometry :: Elementary problems in Euclidean geometries)

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