Let $X$ be a locally compact Hausdorff topological space with Borel $\sigma$ -algebra $\mathcal{B}$ and suppose $\mu$ is a measure on $(X,\mathcal{B})$ For any Borel set $B \in \mathcal{B}$ the measure $\mu$ is said to be outer regular on $B$ if $$ \mu(B) = \inf\,\{ \mu(U) \mid U \supset B,\ U\ \rm{open} \}. $$ We say $\mu$ is inner regular on $B$ if $$ \mu(B) = \sup\,\{ \mu(K) \mid K \subset B,\ K\ \rm{compact} \}. $$