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partial ordering in a topological space (Definition)

Let $ X$ be a T0 space. For any $ x,y\in X$, we define a binary relation $ \le$ on $ X$ as follows:

$\displaystyle x\le y$ iff $\displaystyle x \in \overline{\lbrace y\rbrace}.$

Proposition. The binary relation just defined is a partial order.

Proof. Clearly $ x\le x$. Suppose next that $ x\le y$ and $ y\le x$. If $ x\ne y$, then there is an open set $ A$ such that $ x\in A$ and $ y\notin A$. So $ y\in A^c$, the complement of $ A$, which is a closed set. But then $ x\in A^c$ since it is in the closure of $ \lbrace y\rbrace$. So $ x\in A\cap A^c=\varnothing$, a contradition. Thus $ x=y$. Finally, suppose $ x\le y$ and $ y\le z$. Let $ C$ be a closed set containing $ z$. Since $ y$ is in the closure of $ \lbrace z\rbrace$, $ y\in C$. Since $ x$ is in the closure of $ \lbrace y\rbrace$, $ x\in C$ also. So $ x\le z$. $ \qedsymbol$

This turns the topological space $ X$ into a poset.

$ \le$ is called the specialization order of $ X$. We have the following

$ x\le y$ iff $ x\in U$ implies $ y\in U$ for any open set $ U$ in $ X$
Proof. $ (\Rightarrow):$ if $ x\in U$ and $ y\notin U$, then $ y\in U^c$. Since $ x\le y$, we have $ x\in U^c$, a contradiction. $ (\Leftarrow) :$ if $ x\notin \overline{\lbrace y\rbrace}$, then for some closed set $ C$, we have $ y\in C$ and $ x\notin C$. But then $ x\in C^c$, so that $ y\in C^c$, a contradiction. $ \qedsymbol$

Remarks.



"partial ordering in a topological space" is owned by CWoo.
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See Also: specialization

Also defines:  specialization order
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Cross-references: proof, antisymmetry, closed, singletons, diagonal, Hausdorff space, lower set, preorder, contradiction, implies, iff, poset, topological space, closure, closed set, complement, open set, partial order, proposition, binary relation, T0 space
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This is version 5 of partial ordering in a topological space, born on 2007-01-16, modified 2007-01-18.
Object id is 8775, canonical name is PartialOrderingInATopologicalSpace.
Accessed 832 times total.

Classification:
AMS MSC54F99 (General topology :: Special properties :: Miscellaneous)

Pending Errata and Addenda
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Discussion
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Is this specialization order? by kompik on 2007-01-18 03:56:06
Isn't this the same thing which is usually called specialization order?
http://planetmath.org/encyclopedia/Specialization.html
http://en.wikipedia.org/wiki/Specialization_order
If yes, it should be added into the entry as an alternative name.
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