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Pasch's theorem (Theorem)
Theorem 1   (Pasch) Let $ \triangle abc$ be a triangle with non-collinear vertices $ a,b,c$ in a linear ordered geometry. Suppose a line $ \ell$ intersects one side, say open line segment $ \overline{ab}$, at a point strictly between $ a$ and $ b$, then $ \ell$ also intersects exactly one of the following:
$\displaystyle \overline{bc}$, $\displaystyle \qquad\qquad\overline{ac}$, $\displaystyle \qquad\qquad c.$
Proof. First, note that vertices $ a$ and $ b$ are on opposite sides of line $ \ell$. Then either $ c$ lies on $ \ell$, or $ c$ does not. if $ c$ does not, then it must lie on either side (half plane) of $ \ell$. In other words, $ c$ and $ a$ must be on the opposite sides of $ \ell$, or $ c$ and $ b$ must be on the opposite sides of $ \ell$. If $ c$ and $ a$ are on the opposite sides, $ \ell$ has a non-empty intersection with $ \overline{ac}$. But if $ c$ and $ a$ are on the opposite sides, then $ c$ and $ b$ are on the same side, which means that $ \overline{bc}$ does not intersect $ \ell$. $ \qedsymbol$
Remark A companion property states that if line $ \ell$ passes through one vertex $ a$ of a triangle $ \triangle abc$ and at least one other point on $ \triangle abc$, then it must intersect exactly one of the following:
$\displaystyle b$, $\displaystyle \qquad\qquad c$, $\displaystyle \qquad\qquad\overline{bc}.$
Of course, if $ \ell$ passes through $ b$, $ \overline{ab}$ must lie on $ \ell$. Similarly, $ \overline{ac}$ lies on $ \ell$ if $ \ell$ passes through $ c$.



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See Also: angle, ordered geometry

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Cross-references: vertex, property, half plane, lie on, lies on, opposite sides, strictly, point, open line segment, side, intersects, line, linear ordered geometry, vertices, triangle
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This is version 10 of Pasch's theorem, born on 2005-10-09, modified 2007-07-27.
Object id is 7429, canonical name is PaschsTheorem.
Accessed 2032 times total.

Classification:
AMS MSC51G05 (Geometry :: Ordered geometries )

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