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Pasch's theorem
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(Theorem)
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Proof. First, note that vertices  and  are on opposite sides of line  . Then either lies on  , or  does not. if  does not, then it must lie on either side ( half plane) of  . In other words,  and  must be on the opposite sides of  , or  and  must be on the opposite sides of  . If  and  are on the opposite sides,  has a non-empty intersection with
 . But if  and  are on the opposite sides, then  and  are on the same side, which means that
 does not intersect  . 
Remark A companion property states that if line passes through one vertex of a triangle
and at least one other point on
, then it must intersect exactly one of the following:
Of course, if passes through ,
must lie on . Similarly,
lies on if passes through .
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"Pasch's theorem" is owned by CWoo. [ full author list (2) ]
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Cross-references: vertex, property, half plane, lie on, lies on, opposite sides, strictly, point, open line segment, side, intersects, line, linear ordered geometry, vertices, triangle
There is 1 reference to this entry.
This is version 10 of Pasch's theorem, born on 2005-10-09, modified 2007-07-27.
Object id is 7429, canonical name is PaschsTheorem.
Accessed 2032 times total.
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Pending Errata and Addenda
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