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[parent] proof of general Stokes theorem (Proof)

We divide the proof in several steps.

Step One.

Suppose $ M=(0,1]\times (0,1)^{n-1}$ and

$\displaystyle \omega(x_1,\ldots,x_n)=f(x_1,\ldots,x_n)\, d x_1\wedge\cdots\wedge \widehat{d x_j}\wedge \cdots \wedge d x_n $
(i.e. the term $ dx_j$ is missing). Hence we have
$\displaystyle d\omega(x_1,\ldots,x_n)$ $\displaystyle =$ $\displaystyle \left(\frac{\partial f}{\partial x_1} d x_1+\cdots +\frac{\partia... ...ight)\wedge d x_1\wedge \cdots \wedge \widehat{d x_j}\wedge \cdots \wedge d x_n$  
  $\displaystyle =$ $\displaystyle (-1)^{j-1} \frac{\partial f}{\partial x_j} d x_1\wedge \cdots \wedge d x_n$  

and from the definition of integral on a manifold we get
$\displaystyle \int_M d\omega = \int_0^1\cdots \int_0^1 (-1)^{j-1} \frac{\partial f}{\partial x_j} d x_1 \cdots d x_n. $
From the fundamental theorem of Calculus we get
$\displaystyle \int_M d\omega =(-1)^{j-1} \int_0^1\cdots\widehat{\int_0^1}\cdots... ...dots,x_n)-f(x_1,\ldots,0,\ldots,x_n) d x_1\cdots \widehat{ d x_j}\cdots d x_n. $
Since $ \omega$ and hence $ f$ have compact support in $ M$ we obtain
\begin{displaymath} \int_M d\omega=\left\{ \begin{array}{lcl} \int_0^1\cdots\int... ...\text{if} & j=1 \\ \ 0 &\text{if} & j>1 . \end{array}\right. \end{displaymath}

On the other hand we notice that $ \int_{\partial M}\omega$ is to be understood as $ \int_{\partial M}i^* \omega$ where $ i:\partial M\to M$ is the inclusion map. Hence it is trivial to verify that when $ j\neq 1$ then $ i^*\omega=0$ while if $ j=1$ it holds

$\displaystyle i^*\omega(x) = f(1,x_2,\ldots,x_n) d x_2\wedge\ldots\wedge d x_n $
and hence, as wanted
$\displaystyle \int_{\partial M}i^*\omega = \int_0^1\cdots\int_0^1 f(x) d x_2 \cdots d x_n. $

Step Two.

Suppose now that $ M=[0,1)\times (0,1)^{n-1}$ and let $ \omega$ be any differential form. We can always write

$\displaystyle \omega(x)=\sum_j f_j(x) d x_1 \wedge\cdots \wedge \widehat{ d x_j} \wedge \cdots \wedge d x_n $
and by the additivity of the integral we can reduce ourself to the previous case.

Step Three.

When $ M=(0,1)^n$ we could follow the proof as in the first case and end up with $ \int_M d \omega = 0$ while, in fact, $ \partial M=\emptyset$.

Step Four.

Consider now the general case.

First of all we consider an oriented atlas $ (U_i,\phi_i)$ such that either $ U_i$ is the cube $ (0,1]\times (0,1)^{n-1}$ or $ U_i=(0,1)^n$. This is always possible. In fact given any open set $ U$ in $ [0,+\infty)\times \mathbb{R}^{n-1}$ and a point $ x\in U$ up to translations and rescaling it is possible to find a “cubic” neighbourhood of $ x$ contained in $ U$.

Then consider a partition of unity $ \alpha_i$ for this atlas.

From the properties of the integral on manifolds we have

$\displaystyle \int_{M} d \omega$ $\displaystyle =$ $\displaystyle \sum_i \int_{U_i} \alpha_i \phi^* d \omega = \sum_i \int_{U_i} \alpha_i d (\phi^* \omega)$  
  $\displaystyle =$ $\displaystyle \sum_i \int_{U_i} d (\alpha_i\cdot \phi^*\omega) - \sum_i \int_{U_i} (d\alpha_i)\wedge(\phi^*\omega).$  

The second integral in the last equality is zero since $ \sum_i d\alpha_i= d \sum_i \alpha_i = 0$, while applying the previous steps to the first integral we have

$\displaystyle \int_{M} d\omega = \sum_i \int_{\partial U_i}\alpha_i\cdot \phi^*\omega. $
On the other hand, being $ (\partial U_i,\phi_{\vert\partial U_i})$ an oriented atlas for $ \partial M$ and being $ {\alpha_i}_{\vert\partial U_i}$ a partition of unity, we have
$\displaystyle \int_{\partial M} \omega = \sum_i \int_{\partial U_i} \alpha_i \phi^* \omega $
and the theorem is proved.



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Cross-references: equality, properties, partition of unity, contained, neighbourhood, translations, point, open set, cube, atlas, oriented, additivity, differential form, inclusion map, support, compact, fundamental theorem of calculus, manifold, integral, term, divide

This is version 4 of proof of general Stokes theorem, born on 2003-06-16, modified 2003-06-16.
Object id is 4370, canonical name is ProofOfGeneralStokesTheorem.
Accessed 14214 times total.

Classification:
AMS MSC58C35 (Global analysis, analysis on manifolds :: Calculus on manifolds; nonlinear operators :: Integration on manifolds; measures on manifolds)

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