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proof of Hadamard three-circle theorem
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(Proof)
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Let be holomorphic on a closed annulus
. Let
Let
. Then we have to prove that
For this, let be a real number; the function
is harmonic outside the zeros of . Near the zeros of the above function has values which are large negative. Hence by the maximum modulus principle this function has its maximum on the boundary of the annulus, specifically on the two circles and . Therefore
for all in the annulus. In particular, we get the inequality
Now let be such that the two values inside the parentheses on the right are equal, that is
Then from the previous inequality, we get
which upon substituting the value for gives the result stated in the theorem.
- Lang, S. Complex analysis, Fourth edition. Graduate Texts in Mathematics, 103. Springer-Verlag, New York, 1999. xiv+485 pp. ISBN 0-387-98592-1
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"proof of Hadamard three-circle theorem" is owned by Simone. [ full author list (2) ]
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Cross-references: right, inequality, circles, annulus, boundary, modulus, negative, near, harmonic, function, real number, closed annulus, holomorphic
This is version 2 of proof of Hadamard three-circle theorem, born on 2006-05-31, modified 2006-09-06.
Object id is 7943, canonical name is ProofOfHadamardThreeCircleTheorem.
Accessed 1357 times total.
Classification:
| AMS MSC: | 30A10 (Functions of a complex variable :: General properties :: Inequalities in the complex domain) | | | 30C80 (Functions of a complex variable :: Geometric function theory :: Maximum principle; Schwarz's lemma, Lindelöf principle, analogues and generalizations; subordination) |
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Pending Errata and Addenda
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