PlanetMath (more info)
 Math for the people, by the people.
Encyclopedia | Requests | Forums | Docs | Wiki | Random | RSS  
Login
create new user
name:
pass:
forget your password?
Main Menu
Owner confidence rating: High Entry average rating: Very high
property (Definition)

Let $ X$ be a set. A property $ p$ of $ X$ is a function

$\displaystyle p\colon X\to \{\mathit{true},\mathit{false}\}.$
An element $ x\in X$ is said to have or does not have the property $ p$ depending on whether $ p(x)=\mathit{true}$ or $ p(x)=\mathit{false}$. Any property gives rise in a natural way to the set
$\displaystyle X(p):=\lbrace x\in X \vert \ x$ has property $\displaystyle p\rbrace$
and the corresponding characteristic function $ 1_{X(p)}$. The identification of $ p$ with $ X(p)\subseteq X$ enables us to think of a property of $ X$ as a 1-ary, or a unary relation on $ X$. Therefore, one may treat all these notions equivalently.

Usually, a property $ p$ of $ X$ can be identified with a so-called propositional function, or a predicate $ \varphi(v)$, where $ v$ is a variable or a tuple of variables whose values range over $ X$. The values of a propositional function is a proposition, which can be interpreted as being either “true” or “false”, so that $ X(p)=\lbrace x \mid \varphi(x)$ is $ \mathit{true}\rbrace$.

Below are a few examples:

  • Let $ X=\mathbb{Z}$. Let $ \varphi(v)$ be the propositional function “$ v$ is divisible by $ 3$”. If $ p$ is the property identified with $ \varphi(v)$, then $ X(p)=3\mathbb{Z}$.
  • Again, let $ X=\mathbb{Z}$. Let $ \varphi(v_1,v_2):=$$ v_1$ is divisible by $ v_2$” and $ p$ the corresponding property. Then
    $\displaystyle X(p)=\lbrace (m,n)\mid m=np$, for some $\displaystyle p\in \mathbb{Z}\rbrace,$
    which is a subset of $ X\times X$. So $ p$ is a property of $ X\times X$.
  • The reflexive property of a binary relation on $ X$ can be identified with the propositional function $ \varphi(V):=\lq\lq \forall a\in X$, $ (a,a)\in V$”, and therefore
    $\displaystyle X(p)=\lbrace R\subseteq X\times X\mid \varphi(R)$ is $\displaystyle \mathit{true}\rbrace,$
    which is a subset of $ 2^{X\times X}$. Thus, $ p$ is a property of $ 2^{X\times X}$.
  • In point set topology, we often encounter the finite intersection property on a family of subsets of a given set $ X$. Let
    $\displaystyle \varphi(\mathcal{V}):=\lq\lq \forall n\in \mathbb{N}, \forall E_1\in \... ...ldots,\forall E_n\in \mathcal{V}, \exists x\in X (x\in E_1\cap \cdots \cap E_n)$
    and $ p$ the corresponding property, then
    $\displaystyle X(p)=\lbrace \mathcal{F} \subseteq 2^X\mid \varphi(\mathcal{F})$ is $\displaystyle \mathit{true}\rbrace,$
    which is a subset of $ 2^{2^X}$. Thus $ p$ is a property of $ 2^{2^X}$.



Anyone with an account can edit this entry. Please help improve it!

"property" is owned by drini. [ full author list (7) | owner history (3) ]
(view preamble)

View style:

See Also: subset, characteristic function, relation, closure of a relation with respect to a property

Other names:  attribute, propositional function
Also defines:  unary relation, predicate

Attachments:
characterisation (Definition) by pahio
Log in to rate this entry.
(view current ratings)

Cross-references: finite intersection property, topology, point, binary relation, Reflexive, subset, proposition, range, tuple, variable, function
There are 821 references to this entry.

This is version 12 of property, born on 2003-10-15, modified 2007-11-20.
Object id is 5001, canonical name is Property2.
Accessed 35564 times total.

Classification:
AMS MSC00A05 (General :: General and miscellaneous specific topics :: General mathematics)

Pending Errata and Addenda
None.
[ View all 1 ]
Discussion
Style: Expand: Order:
forum policy
addition to property by marijke on 2005-04-03 01:05:53
Hi drini,

added a bit to the "property" topic, what do you think?

You already said
> Given any element of a set $X$
I'm just adding why we do it that way.

--regards, marijke
 http://web.mat.bham.ac.uk/marijke/
[ reply | up ]

Interact
post | correct | update request | add derivation | add example | add (any)