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radius of convergence of a complex function (Theorem)

Let $ f$ be an analytic function defined in a disk of radius $ R$ about a point $ z_0 \in \mathbb{C}$. Then the radius of convergence of the Taylor series of $ f$ about $ z_0$ is at least $ R$.

For example, the function $ a(z) = 1 / (1 - z)^2$ is analytic inside the disk $ \vert z\vert < 1$. Hence its the radius of covergence of its Taylor series about 0 is at least $ 1$. By direct examination of the Taylor series we can see that its radius of convergence is, in fact, equal to $ 1$.

Colloquially, this theorem is stated in the sometimes imprecise but memorable form “The radius of convergence of the Taylor series is the distance to the nearest singularity.”



"radius of convergence of a complex function" is owned by rspuzio.
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proof of radius of convergence of a complex function (Proof) by rspuzio
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Cross-references: function, Taylor series, radius of convergence, point, radius, analytic function
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This is version 3 of radius of convergence of a complex function, born on 2004-10-03, modified 2004-10-05.
Object id is 6278, canonical name is RadiusOfConvergenceOfAComplexFunction.
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AMS MSC30B10 (Functions of a complex variable :: Series expansions :: Power series )

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