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[parent] separated uniform space (Definition)

Let $X$ be a uniform space with uniformity $\mathcal{U}$ . $X$ is said to be separated or Hausdorff if it satisfies the following separation axiom: $$\bigcap \mathcal{U}=\Delta,$$ where $\Delta$ is the diagonal relation on $X$ and $\bigcap \mathcal{U}$ is the intersection of all elements (entourages) in $\mathcal{U}$ . Since $\Delta\subseteq \bigcap \mathcal{U}$ , the separation axiom says that the only elements that belong to every entourage of $\mathcal{U}$ are precisely the diagonal elements $(x,x)$ . Equivalently, if $x\ne y$ , then there is an entourage $U$ such that $(x,y)\notin U$ .

The reason for calling $X$ separated has to do with the following assertion:

$X$ is separated iff $X$ is a Hausdorff space under the topology $T_{\mathcal{U}}$ induced by $\mathcal{U}$ .

Recall that $T_{\mathcal{U}}=\lbrace A\subseteq X\mid \mbox{for each }x\in A\mbox{, there is }U\in \mathcal{U}\mbox{, such that }U[x]\subseteq A\rbrace$ , where $U[x]$ is some uniform neighborhood of $x$ where, under $T_{\mathcal{U}}$ , $U[x]$ is also a neighborhood of $x$ . To say that $X$ is Hausdorff under $T_{\mathcal{U}}$ is the same as saying every pair of distinct points in $X$ have disjoint uniform neighborhoods.

Proof. $(\Rightarrow)$ . Suppose $X$ is separated and $x,y\in X$ are distinct. Then $(x,y)\notin U$ for some $U\in \mathcal{U}$ . Pick $V\in \mathcal{U}$ with $V\circ V\subseteq U$ . Set $W=V\cap V^{-1}$ , then $W$ is symmetric and $W\subseteq V$ . Furthermore, $W\circ W\subseteq V\circ V\subseteq U$ . If $z\in W[x]\cap W[y]$ , then $(x,z),(y,z)\in W$ . Since $W$ is symmetric, $(z,y)\in W$ , so $(x,y)=(x,z)\circ (z,y)\in W\circ W\subseteq U$ , which is a contradiction.

$(\Leftarrow)$ . Suppose $X$ is Hausdorff under $T_{\mathcal{U}}$ and $(x,y)\in U$ for every $U\in \mathcal{U}$ for some $x,y\in X$ . If $x\ne y$ , then there are $V[x]\cap W[y]=\varnothing$ for some $V,W\in \mathcal{U}$ . Since $(x,y)\in V$ by assumption, $y\in V[x]$ . But $y\in W[y]$ , contradicting the disjointness of $V[x]$ and $W[y]$ . Therefore $x=y$ . $ \qedsymbol$




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Other names:  separating, Hausdorff uniform space

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Cross-references: contradiction, symmetric, disjoint, points, neighborhood, uniform neighborhood, topology, Hausdorff space, iff, diagonal, entourages, intersection, diagonal relation, Hausdorff, uniformity, uniform space
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This is version 2 of separated uniform space, born on 2007-02-18, modified 2008-06-02.
Object id is 8925, canonical name is SeparatedUniformSpace.
Accessed 1805 times total.

Classification:
AMS MSC54E15 (General topology :: Spaces with richer structures :: Uniform structures and generalizations)

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