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[parent] Schur's inequality (Theorem)

Theorem (Schur's inequality) Let $ A$ be a square $ n\times n$ matrix with real (or possibly complex entries). If $ \lambda_1,\ldots, \lambda_n$ are the eigenvalues of $ A$, and $ D$ is the diagonal matrix $ D=\operatorname{diag}(\lambda_1,\ldots, \lambda_n)$, then

$\displaystyle \Vert D \Vert_F$ $\displaystyle \le$ $\displaystyle \Vert A \Vert_F,$  

where $ \Vert\cdot \Vert_F$ is the Frobenius matrix norm. Equality holds if and only if $ A$ is a normal matrix.

References

1
V.V. Prasolov, Problems and Theorems in Linear Algebra, American Mathematical Society, 1994.



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See Also: trace of a matrix, Wielandt-Hoffman theorem, Frobenius matrix norm


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proof of Schur's inequality (Proof) by Andrea Ambrosio
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Cross-references: normal matrix, equality, Frobenius matrix norm, diagonal matrix, eigenvalues, complex, real, matrix, square
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This is version 11 of Schur's inequality, born on 2003-06-28, modified 2006-06-12.
Object id is 4410, canonical name is ShursInequality.
Accessed 5131 times total.

Classification:
AMS MSC15A42 (Linear and multilinear algebra; matrix theory :: Inequalities involving eigenvalues and eigenvectors)
 26D15 (Real functions :: Inequalities :: Inequalities for sums, series and integrals)

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