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[parent] slower divergent series (Theorem)
Theorem 1   If
$\displaystyle a_1\!+\!a_2\!+\!a_3\!+\cdots$ (1)

is a diverging series with positive terms, then one can always form another diverging series
$\displaystyle s_1\!+\!s_2\!+\!s_3\!+\cdots$
with positive terms such that
$\displaystyle \lim_{n\to\infty}\frac{s_n}{a_n} = 0.$ (2)

Proof. Let $ S_n = a_1\!+\!a_2\!+\cdots+\!a_n$ be the $ n^\mathrm{th}$ partial sum of (1). Then we have

$\displaystyle a_n = S_n\!-\!S_{n-1} = (\sqrt{S_n}\!+\!\sqrt{S_{n-1}})(\sqrt{S_n}\!-\!\sqrt{S_{n-1}}).$
We set $ s_1 := \sqrt{S_1}$ and
$\displaystyle s_n := \frac{a_n}{\sqrt{S_n}\!+\!\sqrt{S_{n-1}}} = \sqrt{S_n}\!-\!\sqrt{S_{n-1}}$
for $ n = 2,\,3,\,4,\,\ldots$ Then the terms of the series
$\displaystyle \sum_{n = 1}^{\infty}s_n = \sqrt{S_1}\!+\!\sum_{n = 1}^{\infty}(\sqrt{S_{n+1}}\!-\!\sqrt{S_n})$
apparently are positive. This series is however divergent, because the sum of its $ n$ first terms is equal to $ \sqrt{S_n}$ which grows without bound along with $ n$ since (1) diverges. For this reason we also get the result (2).

Remark. Niels Henrik Abel has presented a simpler example on such series $ s_1\!+\!s_2\!+\!s_3\!+\cdots$:

$\displaystyle 1\!+\!\frac{a_2}{a_1\!+\!a_2}\!+\!\frac{a_3}{a_1\!+\!a_2\!+\!a_3}\! +\!\frac{a_4}{a_1\!+\!a_2\!+\!a_3\!+\!a_4}\!+\cdots$



"slower divergent series" is owned by pahio.
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See Also: slower convergent series, non-existence of universal series convergence criterion


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proof of slower divergent series (Proof) by rspuzio
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Cross-references: diverges, bound, sum, divergent, partial sum, positive, series, diverging
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This is version 10 of slower divergent series, born on 2005-03-19, modified 2006-09-27.
Object id is 6885, canonical name is SlowerDivergentSeries.
Accessed 1721 times total.

Classification:
AMS MSC40A05 (Sequences, series, summability :: Convergence and divergence of infinite limiting processes :: Convergence and divergence of series and sequences)

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