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This is another, shorter, proof for the fact that
always holds.
Let be a partially ordered set and
be a collection of subsets of . We remember that a filter on is
-generic if
for all
which are dense in . (In this context “dense” means: If is dense in , then for every there's a such that .)
Let be a partially ordered set and
a countable collection of dense subsets of . Then there exists a
-generic filter on . Moreover, it could be shown that for every there's such a
-generic filter with .
Proof. Let
 be the dense subsets in
 . Furthermore let  . Now we can choose for every
 an element  such that
 and
 . If we now consider the set
s.t.  , then it is easy to check that  is a
 -generic filter on  and  obviously. This completes the proof. 
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