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subsequence (Definition)

Given a sequence $ \{x_n\}_{n\in \mathbb{N}}$, any infinite subset of the sequence forms a subsequence. We formalize this as follows:

Definition 1   If $ X$ is a set and $ \{a_n\}_{n \in \mathbb{N}}$ is a sequence in $ X$, then a subsequence of $ \{a_n\}$ is a sequence of the form $ \{a_{n_r}\}_{r \in \mathbb{N}}$ where $ \{n_r\}_{r \in \mathbb{N}}$ is a strictly increasing sequence of natural numbers.

Equivalently, $ \{y_n\}_{n\in \mathbb{N}}$ is a subsequence of $ \{x_n\}_{n\in \mathbb{N}}$ if

  1. $ \{y_n\}_{n\in\mathbb{N}}$ is a sequence of elements of $ X$, and
  2. there is a strictly increasing function $ a:\mathbb{N}\to \mathbb{N}$ such that
    $\displaystyle y_n = x_{a(n)}$    for all $\displaystyle n\in\mathbb{N}.$
Example 1   Let $ X=\mathbb{R}$ and let $ \{x_n\}$ be the sequence
$\displaystyle \left\{\frac{1}{n}\right\}_{n\in\mathbb{N}}=\left\{1,\frac{1}{2},\frac{1}{3},\frac{1}{4},\ldots\right\}.$
Then, the sequence
$\displaystyle \{y_n\}_{n\in\mathbb{N}}=\left\{\frac{1}{n^2}\right\}_{n\in\mathbb{N}}=\left\{1,\frac{1}{4},\frac{1}{9},\frac{1}{16},\ldots\right\}$
is a subsequence of $ \{x_n\}$. The subsequence of natural numbers mentioned in the definition is $ \{n^2\}_{n\in\mathbb{N}}$ and the function $ a:\mathbb{N}\to\mathbb{N}$ mentioned above is $ a(n)=n^2$.



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Cross-references: function, natural numbers, strictly increasing, infinite subset, sequence
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This is version 3 of subsequence, born on 2002-08-16, modified 2007-06-22.
Object id is 3300, canonical name is Subsequence.
Accessed 5032 times total.

Classification:
AMS MSC00A05 (General :: General and miscellaneous specific topics :: General mathematics)

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