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Proof. If is a diagonal matrix, then the complex conjugate is also a diagonal matrix. Since arbitrary diagonal matrices commute, it follows that
. Thus any diagonal matrix is a normal triangular matrix.
Next, suppose
is a normal upper triangular matrix. Thus for , so for the diagonal elements in and , we obtain
For , we have
It follows that the only non-zero entry on the first row of is . Similarly, for , we obtain
Since , it follows that the only non-zero element on the second row is . Repeating this argument for all rows, we see that is a diagonal matrix. Thus any normal upper triangular matrix is a diagonal matrix.
Suppose then that is a normal lower triangular matrix. Then it is not difficult to see that is a normal upper triangular matrix. Thus, by the above, is a diagonal matrix, whence also is a diagonal matrix. 
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- V.V. Prasolov, Problems and Theorems in Linear Algebra, American Mathematical Society, 1994.
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