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theorem on constructible angles
- An angle of measure $\theta$ is constructible;
- $\sin \theta$ is a constructible number;
- $\cos \theta$ is a constructible number.
- If an angle whose measure is $\theta$ is constructible, then so are angles whose measures are $\pi-\theta$ , $\pi+\theta$ , and $2\pi-\theta$ ;
- If $x$ is a constructible number, then so is $|x|$ .
If $\theta \in \{0, \frac{\pi}{2} \}$ , then clearly an angle of measure $\theta$ is constructible, and $\{\sin \theta, \cos \theta \}=\{0,1\}$ . Thus, equivalence has been established in the case that $\theta \in \{0,\frac{\pi}{2}\}$ . Therefore, we can restrict our attention even further to the interval $0<\theta<\frac{\pi}{2}$ .
Assume that an angle of measure $\theta$ is constructible. Construct such an angle and mark off a line segment of length $1$ from the vertex of the angle. Label the endpoint that is not the vertex of the angle as $A$ .
{.} \rp... ...](0,0){3}{50}{70} \psdots(0,0)(1.5,2.598) \rput[b](1.2,2.3){$A$} \end{pspicture}](http://images.planetmath.org/cache/objects/9605/js/img2.png)
Drop the perpendicular from $A$ to the other ray of the angle. Since the legs of the triangle are of lengths $\sin \theta$ and $\cos \theta$ , both of these are constructible numbers.
{.} \rp... ...put[a](0.7,-0.3){$\cos \theta$} \rput[l](1.7,1.3){$\sin \theta$} \end{pspicture}](http://images.planetmath.org/cache/objects/9605/js/img3.png)
Now assume that $\sin \theta$ is a constructible number. At one endpoint of a line segment of length $\sin \theta$ , erect the perpendicular to the line segment.
{.} \rput[r](3,0){.} \rput[a](2.59... ...ne[linecolor=blue]{<->}(2.598,-1)(2.598,2) \psdots(0,0)(2.598,0) \end{pspicture}](http://images.planetmath.org/cache/objects/9605/js/img4.png)
From the other endpoint of the given line segment, draw an arc of a circle with radius $1$ so that it intersects the erected perpendicular. Label this point of intersection as $A$ . Connect $A$ to the endpoint of the line segment which was used to draw the arc. Then an angle of measure $\theta$ and a line segment of length $\cos \theta$ have been constructed.
{.} \r... ...\theta$} \psdots(0,0)(2.598,0)(2.598,1.5) \rput[b](2.3,1.5){$A$} \end{pspicture}](http://images.planetmath.org/cache/objects/9605/js/img5.png)
A similar procedure can be used given that $\cos \theta$ is a constructible number to prove the other two statements. ![]()
Note that, if $\cos \theta \neq 0$ , then any of the three statements thus implies that $\tan \theta$ is a constructible number. Moreover, if $\tan \theta$ is constructible, then a right triangle having a leg of length $1$ and another leg of length $\tan \theta$ is constructible, which implies that the three listed conditions are true.
