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[parent] uniqueness of additive identity in a ring (Theorem)
Lemma 1   Let $ R$ be a ring. There exists a unique element 0 in $ R$ such that for all $ a$ in $ R$:
$\displaystyle 0+a=a+0=a.$
Proof. By the definition of ring, there exists at least one identity in $ R$, call it $ 0_1$. Suppose $ 0_2\in R$ is an element which also the of additive identity. Thus,
$\displaystyle 0_2+0_1=0_2$
On the other hand, $ 0_1$ is an additive identity, therefore:
$\displaystyle 0_2+0_1=0_1+0_2=0_1$
Hence $ 0_2=0_1$, i.e. there is a unique additive identity. $ \qedsymbol$



"uniqueness of additive identity in a ring" is owned by alozano.
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Cross-references: identity, ring
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This is version 3 of uniqueness of additive identity in a ring, born on 2004-03-09, modified 2004-11-22.
Object id is 5676, canonical name is UniquenessOfAdditiveIdentityInARing2.
Accessed 2822 times total.

Classification:
AMS MSC13-00 (Commutative rings and algebras :: General reference works )
 16-00 (Associative rings and algebras :: General reference works )
 20-00 (Group theory and generalizations :: General reference works )

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