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[parent] proof of arithmetic-geometric-harmonic means inequality (Example)

We can use the Jensen inequality for an easy proof of the arithmetic-geometric-harmonic means inequality.

Let $x_1,\ldots,x_n > 0$ ; we shall first prove that $$ \sqrt[n]{x_1\cdot\ldots\cdot x_n} \le \frac{x_1+\ldots+x_n}{n}. $$

Note that $\log$ is a concave function. Applying it to the arithmetic mean of $x_1,\ldots, x_n$ and using Jensen's inequality, we see that

$\displaystyle \log(\frac{x_1+\ldots+x_n}{n})$ $\displaystyle \geq\frac{\log(x_1)+\ldots+\log(x_n)}{n}$    
  $\displaystyle =\frac{\log(x_1\cdot\ldots\cdot x_n)}{n}$    
  $\displaystyle =\log{\sqrt[n]{x_1\cdot\ldots\cdot x_n}}.$    

Since $\log$ is also a monotone function, it follows that the arithmetic mean is at least as large as the geometric mean.

The proof that the geometric mean is at least as large as the harmonic mean is the usual one (see ``proof of arithmetic-geometric-harmonic means inequality'').




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See Also: arithmetic-geometric-harmonic means inequality, proof of arithmetic-geometric means inequality using Lagrange multipliers


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Cross-references: harmonic mean, geometric mean, monotone function, arithmetic mean, concave function, arithmetic-geometric-harmonic means inequality, proof, Jensen inequality

This is version 4 of proof of arithmetic-geometric-harmonic means inequality, born on 2002-06-03, modified 2003-08-04.
Object id is 3013, canonical name is UsingJensensInequalityToProveTheArithmeticGeometricHarmonicMeansInequality.
Accessed 10696 times total.

Classification:
AMS MSC39B62 (Difference and functional equations :: Functional equations and inequalities :: Functional inequalities, including subadditivity, convexity, etc.)
 26D15 (Real functions :: Inequalities :: Inequalities for sums, series and integrals)

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