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[parent] values of the Riemann zeta function in terms of Bernoulli numbers (Theorem)
Theorem 1   Let $ k$ be an even integer and let $ B_k$ be the $ k$th Bernoulli number. Let $ \zeta(s)$ be the Riemann zeta function. Then:
$\displaystyle \zeta(k)=\frac{2^{k-1}\vert B_k\vert\pi^k}{k!}$
Moreover, by using the functional equation , one calculates for all $ n\geq 1$:
$\displaystyle \zeta(1-n)=\frac{(-1)^{n+1}B_n}{n}$
which shows that $ \zeta(1-n)=0$ for $ n\geq 3$ odd. For $ k\geq 2$ even, one has:
$\displaystyle \zeta(1-k)=-\frac{B_k}{k}.$
Remark 1   The zeroes of the zeta function shown above, $ \zeta(1-n)=0$ for $ n\geq 3$ odd, are usually called the trivial zeroes of the Riemann zeta function, while the non-trivial zeroes are those in the critical strip.



"values of the Riemann zeta function in terms of Bernoulli numbers" is owned by Mathprof. [ full author list (2) | owner history (1) ]
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See Also: Bernoulli number, value of the Riemann zeta function at $s=2$


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proof of values of the Riemann zeta function in terms of Bernoulli numbers (Proof) by rm50
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Cross-references: critical strip, even, odd, calculates, Riemann zeta function, Bernoulli number, even integer
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This is version 4 of values of the Riemann zeta function in terms of Bernoulli numbers, born on 2005-04-20, modified 2006-10-02.
Object id is 6960, canonical name is ValuesOfTheRiemannZetaFunctionInTermsOfBernoulliNumbers.
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AMS MSC11M99 (Number theory :: Zeta and $L$-functions: analytic theory :: Miscellaneous)

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about Alozano's Riemann Z function entry by perucho on 2005-04-24 04:03:51
It is precise to clarify that the zeroes of Riemann Z function which it appear in the Alozano's entry, are all zeros trivial ones.
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