PlanetMath (more info)
 Math for the people, by the people. Sponsor PlanetMath
Encyclopedia | Requests | Forums | Docs | Wiki | Random | RSS  
Login
create new user
name:
pass:
forget your password?
Main Menu
Owner confidence rating: Medium Entry average rating: No information on entry rating
Vitali's Theorem (Theorem)

There exists a set $V\subset [0,1]$ which is not Lebesgue measurable. Notice that this result requires the Axiom of Choice.




"Vitali's Theorem" is owned by paolini.
(view preamble | get metadata)

View style:

See Also: Lebesgue integral, Lebesgue measure, pseudoparadox in measure theory, example of function not Lebesgue Measurable with measurable level sets

Other names:  existence of non measurable sets

Attachments:
proof of Vitali's Theorem (Proof) by paolini
example of function not Lebesgue Measurable with measurable level sets (Example) by cvalente
Log in to rate this entry.
(view current ratings)

Cross-references: axiom of choice, Lebesgue measurable
There are 3 references to this entry.

This is version 2 of Vitali's Theorem, born on 2003-07-17, modified 2004-03-31.
Object id is 4466, canonical name is VitalisTheorem.
Accessed 7378 times total.

Classification:
AMS MSC28Axx (Classical measure theory)

Pending Errata and Addenda
None.
[ View all 2 ]
Discussion
Style: Expand: Order:
forum policy

No messages.

Interact
post | correct | update request | prove | add result | add corollary | add example | add (any)