PlanetMath (more info)
 Math for the people, by the people.
Encyclopedia | Requests | Forums | Docs | Wiki | Random | RSS  
Login
create new user
name:
pass:
forget your password?
Main Menu
Owner confidence rating: Very high Entry average rating: No information on entry rating
[parent] yet another proof of parallelogram law (Proof)

Define $ g(\epsilon) = \langle x+\epsilon y , x + \epsilon y\rangle$, where $ \epsilon$ is real. Then $ g(\epsilon) = \langle x,x\rangle + \epsilon (\langle y,x\rangle + \langle x,y\rangle) + \epsilon^2 \langle y,y\rangle .$ Hence,

$\displaystyle \Vert x + y \Vert ^2 + \Vert x - y \Vert ^2 = g(1) + g(-1) = 2\langle x,x\rangle + 2\langle y,y\rangle = 2 \Vert x \Vert ^2 + 2 \Vert y \Vert ^2.$



"yet another proof of parallelogram law" is owned by Mathprof.
(view preamble)

View style:


This object's parent.
Log in to rate this entry.
(view current ratings)

Cross-references: real

This is version 2 of yet another proof of parallelogram law, born on 2006-08-03, modified 2006-08-04.
Object id is 8214, canonical name is YetAnotherProofOfParallelogramLaw.
Accessed 856 times total.

Classification:
AMS MSC46C05 (Functional analysis :: Inner product spaces and their generalizations, Hilbert spaces :: Hilbert and pre-Hilbert spaces: geometry and topology )

Pending Errata and Addenda
None.
[ View all 1 ]
Discussion
Style: Expand: Order:
forum policy

No messages.

Interact
post | correct | update request | add example | add (any)