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Yoneda lemma (Theorem)

If $\mathcal{C}$ is a category, write $\hat{\mathcal{C}}$ for the category of contravariant functors from $\mathcal{C}$ to ${\bf Sets}$ the category of sets. The morphisms in $\hat{\mathcal{C}}$ are natural transformations of functors.

(To avoid set theoretical concerns, one can take a universe $\mathcal{U}$ and take all categories to be $\mathcal{U}$ small.)

For any object $X$ of $\mathcal{C}$ $h_X = {\rm Hom}(-,X)$ is a contravariant functor from $\mathcal{C}$ to ${\bf Sets}$ and therefore is an object of $\hat{\mathcal{C}}$

Yoneda Lemma says that $X\mapsto h_X$ is a covariant functor $\mathcal{C}\to\hat{\mathcal{C}}$ which embeds $\mathcal{C}$ faithfully as a full subcategory of $\hat{\mathcal{C}}$ This embedding is called the Yoneda embedding.




"Yoneda lemma" is owned by rspuzio. [ full author list (4) | owner history (3) ]
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See Also: concrete category

Other names:  Yoneda's Lemma
Also defines:  Yoneda embedding

Attachments:
proof of Yoneda lemma (Proof) by GodelsTheorem
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Cross-references: embedding, full subcategory, faithfully, object, universe, natural transformations, morphisms, category of sets, contravariant functors, category
There are 5 references to this entry.

This is version 9 of Yoneda lemma, born on 2002-02-02, modified 2008-05-01.
Object id is 1638, canonical name is YonedaEmbedding.
Accessed 8180 times total.

Classification:
AMS MSC18A25 (Category theory; homological algebra :: General theory of categories and functors :: Functor categories, comma categories)

Pending Errata and Addenda
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what about the yoneda product? by Spimijanman on 2005-03-14 23:10:54
i know they are different, err different fields even, but i am trying to get a good formal definitiion, thanx fer yer time
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