Euclid’s lemma proof
We have a|bc, so bc=na, with n an integer. Dividing both sides by a, we have
bca=n |
But gcd(a,b)=1 implies b/a is only an integer if a=1. So
bca=bca=n |
which means a must divide c.
Note that this proof relies on the Fundamental Theorem of Arithmetic. The alternative proof of Euclid’s lemma avoids this.
Title | Euclid’s lemma proof |
---|---|
Canonical name | EuclidsLemmaProof |
Date of creation | 2013-03-22 11:47:11 |
Last modified on | 2013-03-22 11:47:11 |
Owner | akrowne (2) |
Last modified by | akrowne (2) |
Numerical id | 9 |
Author | akrowne (2) |
Entry type | Proof |
Classification | msc 17B80 |
Classification | msc 81T30 |
Classification | msc 11A05 |
Classification | msc 81-00 |