Fuglede-Putnam-Rosenblum theorem
Let A be a C∗-algebra with unit e.
The Fuglede-Putnam-Rosenblum theorem makes the assertion that for a normal element a∈A the kernel of the commutator mapping [a,-]:A→A is a ∗-closed set.
The general formulation of the result is as follows:
Theorem. Let A be a C∗-algebra with unit e. Let two normal elements a,b∈A be given and c∈A with ac=cb. Then it follows that a∗c=cb∗.
Lemma. For any x∈A we have that exp(x-x∗) is a element of A.
Proof. We have for x∈A that exp(x-x∗)∗exp(x-x∗)=exp(x∗-x+x-x∗)=exp(0)=e. And similarly exp(x-x∗)exp(x-x∗)∗=e. ∎
With this we can now give a proof the Theorem.
Proof. The condition ac=cb implies by induction that akc=cbk holds for each k∈ℕ.
Expanding in power series
on both sides yields exp(a)c=cexp(b).
This is equivalent
to c=exp(-a)cexp(b). Set U1:=. From the Lemma we obtain that .
Since commutes with und with we obtain that
which equals .
Hence
Define by . If we substitute in the last estimate we obtain
But is clearly an entire function and therefore Liouville’s theorem implies that for each .
This yields the equality
Comparing the terms of first order for small finishes the proof. ∎
Title | Fuglede-Putnam-Rosenblum theorem |
---|---|
Canonical name | FugledePutnamRosenblumTheorem |
Date of creation | 2013-05-08 21:47:27 |
Last modified on | 2013-05-08 21:47:27 |
Owner | karstenb (16623) |
Last modified by | karstenb (16623) |
Numerical id | 1 |
Author | karstenb (16623) |
Entry type | Theorem |
Classification | msc 47L30 |