full families of Hopfian (co-Hopfian) groups
Proposition. Let {Gi}i∈I be a full family of groups. Then each Gi is Hopfian (co-Hopfian) if and only if ⊕i∈IGi is Hopfian (co-Hopfian).
Proof. ,,⇒” Let
f:⊕i∈IGi→⊕i∈IGi |
be a surjective (injective
) homomorphism
. Since {Gi}i∈I is full, then there exists family of homomorphisms {fi:Gi→Gi}i∈I such that
f=⊕i∈Ifi. |
Of course since f is surjective (injective), then each fi is surjective (injective). Thus each fi is an isomorphism, because each Gi is Hopfian (co-Hopfian). Therefore f is an isomorphism, because
f-1=⊕i∈If-1i. |
,,” Fix and assume that is a surjective (injective) homomorphism. For such that define to be any automorphism of . Then
is a surjective (injective) group homomorphism. Since is Hopfian (co-Hopfian) then is an isomorphism. Thus each is an isomorphism. In particular is an isomorphism, which completes the proof.
Example. Let and be any subset of . Then
is both Hopfian and co-Hopfian.
Proof. It is easy to see that is full, so is also full. Moreover for any the group is finite, so both Hopfian and co-Hopfian. Therefore (due to proposition)
is both Hopfian and co-Hopfian.
Title | full families of Hopfian (co-Hopfian) groups |
---|---|
Canonical name | FullFamiliesOfHopfiancoHopfianGroups |
Date of creation | 2013-03-22 18:36:05 |
Last modified on | 2013-03-22 18:36:05 |
Owner | joking (16130) |
Last modified by | joking (16130) |
Numerical id | 7 |
Author | joking (16130) |
Entry type | Theorem |
Classification | msc 20A99 |