Green’s function for differential operator
Assume we are given g∈𝒞0([0,T]) and we want to find f∈𝒞1([0,T]) such that
{f′(t)=g(t)f(0)=0 | (1) |
Expression (1) is an example of initial value problem for an ordinary differential equation
. Let us
show, that (1) can be put into the framework of the definition for Green’s function.
-
1.
Ωx=Ωy=[0,T].
-
2.
ℱ(Ωx)={f∈𝒞1([0,T])|f(0)=0}
𝒢(Ωy)=𝒞0([0,T]). -
3.
Af=f′
Thus (1) can be written as an operator equation
Af=g. | (2) |
To find the Green’s function for (2) we proceed as follows:
f(t)=δt(A-1g)=t∫0g(t′)𝑑t′=T∫0G(t,t′)g(t′)𝑑t′, |
where G(t,t′) has the following form:
G(t,t′)={1,0≤t≤t′0,t′<t≤T | (3) |
Thus, function (3) is the Green’s function for the operator equation (2) and then for the problem (1).
Its graph is presented in Figure 1.
Title | Green’s function for differential operator![]() |
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Canonical name | GreensFunctionForDifferentialOperator |
Date of creation | 2013-03-22 14:43:39 |
Last modified on | 2013-03-22 14:43:39 |
Owner | mathforever (4370) |
Last modified by | mathforever (4370) |
Numerical id | 7 |
Author | mathforever (4370) |
Entry type | Example |
Classification | msc 34A99 |
Classification | msc 34A30 |