least surface of revolution
The points and have to be by an arc such that when it rotates around the -axis, the area of the surface of revolution (http://planetmath.org/SurfaceOfRevolution) formed by it is as small as possible.
The area in question, expressed by the path integral
| (1) |
along , is to be minimised; i.e. we must minimise
| (2) |
Since the integrand in (2) does not explicitly depend on , the Euler–Lagrange differential equation![]()
(http://planetmath.org/EulerLagrangeDifferentialEquation) of the problem, the necessary condition for (2) to give an extremal , reduces to the Beltrami identity
where is a constant of integration. After solving this equation for the derivative and separation of variables![]()
, we get
by integration of which we choose the new constant of integration such that when :
We can write two equivalent (http://planetmath.org/Equivalent3) results
i.e.
Adding these yields
| (3) |
From this we see that the extremals of the problem are catenaries. It means that the least surface of revolution in the question is a catenoid.
| Title | least surface of revolution |
| Canonical name | LeastSurfaceOfRevolution |
| Date of creation | 2013-03-22 19:12:11 |
| Last modified on | 2013-03-22 19:12:11 |
| Owner | pahio (2872) |
| Last modified by | pahio (2872) |
| Numerical id | 6 |
| Author | pahio (2872) |
| Entry type | Example |
| Classification | msc 49K05 |
| Classification | msc 53A05 |
| Classification | msc 26B15 |
| Related topic | MinimalSurface |
| Related topic | EquationOfCatenaryViaCalculusOfVariations |
| Related topic | Catenary |
| Related topic | MinimalSurface2 |
| Related topic | CalculusOfVariations |
| Related topic | SurfaceOfRevolution2 |