line through an intersection point
Suppose that the lines
Ax+By+C=0andA′x+B′y+C′=0 | (1) |
have an intersection point. Then for any real value of k, the equation
Ax+By+C+k(A′x+B′y+C′)=0 | (2) |
represents a line passing through that point.
In fact, the of the equation (2) is 1, and therefore it represents a line; secondly, (2) is satisfied if both equations (1) are satisfied, and therefore the line passes through that intersection point.
Example. Determine the equation of the line passing through the point (-5, 2) and the intersection point of the lines 6x-7y+9=0 and 5x+9y-3=0.
The equation of a line through the common point of those lines is
6x-7y+9+k(5x+9y-3)=0. | (3) |
We have to find such a value for k that also (-5, 2) lies on the line, i.e. that the equation (3) is satisfied by the values x=-5, y=2. So we get for determining k the equation
-35-10k=0, |
whence k=-72. Using this value in (3), multiplying the equation by 2 and simplifying, we obtain the sought equation
23x+77y-39=0. |
This result would be obtained, of course, by first calculating the intersection point of the two given lines (it is (-6089,6389)) and then forming the equation of the line passing this point and the point (-5, 2), but then the calculations would have been substantially longer.
Note. It is apparent that no value of k allows the equation (2) to the line
A′x+B′y+C′=0 itself. Thus, if we had in the example instead the point (-5, 2) e.g. the point (6,-3) of the line 5x+9y-3=0, then we had the condition 66+0k=0 which gives no value of k.
References
- 1 K. Väisälä: Algebran oppi- ja esimerkkikirja II. Neljäs painos. Werner Söderström osakeyhtiö, Porvoo & Helsinki (1956).
Title | line through an intersection point |
---|---|
Canonical name | LineThroughAnIntersectionPoint |
Date of creation | 2013-03-22 17:30:28 |
Last modified on | 2013-03-22 17:30:28 |
Owner | pahio (2872) |
Last modified by | pahio (2872) |
Numerical id | 8 |
Author | pahio (2872) |
Entry type | Topic |
Classification | msc 53A04 |
Classification | msc 51N20 |