is not a countable union of proper vector subspaces
is not a countable union of proper vector subspaces.
Proof
We know that every finite dimensional proper subspace of a normed space is nowhere dense. Besides, is a Banach space, so the results follows directly.
Title | is not a countable union of proper vector subspaces |
---|---|
Canonical name | mathbbRnIsNotACountableUnionOfProperVectorSubspaces |
Date of creation | 2013-03-22 14:59:03 |
Last modified on | 2013-03-22 14:59:03 |
Owner | rspuzio (6075) |
Last modified by | rspuzio (6075) |
Numerical id | 6 |
Author | rspuzio (6075) |
Entry type | Result |
Classification | msc 54E52 |