alg. geometry

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# alg. geometry

Submitted by michaelangelo on Tue, 01/09/2007 - 14:49

Forums:

how can we show that

"ideal of an algebraic variety is radical"

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## Versions

(v1) by michaelangelo 2007-01-09

## Re: alg. geometry

hint: if f^n lies in the ideal I of the variety V, then f^n(x)=0 for every x in V. If we're working over a field, f(x) = 0 for all x in V, so f lies in I too. Therefore the radical of I is contained in I.