proof that components of open sets in a locally connected space are open
Theorem.
A topological space X is locally connected if and only if each component of an open set
is open.
Proof.
First, suppose that X is locally connected and that U is an open set of X. Let p∈C, where C is a component of U. Since X is locally connected there is an open connected set, say V with p∈V⊂U. Since C is a component of U it must be that V⊂C. Hence, C is open. For the converse, suppose that each component of each open set is open. Let p∈X. Let U be an open set containing p. Let C be the component of U which contains p. Then C is open and connected, so X is locally connected.
∎
As a corollary, we have that the components of a locally connected space are both open and closed.
Title | proof that components of open sets in a locally connected space are open |
---|---|
Canonical name | ProofThatComponentsOfOpenSetsInALocallyConnectedSpaceAreOpen |
Date of creation | 2013-03-22 17:06:07 |
Last modified on | 2013-03-22 17:06:07 |
Owner | Mathprof (13753) |
Last modified by | Mathprof (13753) |
Numerical id | 6 |
Author | Mathprof (13753) |
Entry type | Theorem |
Classification | msc 54A99 |