Taylor expansion of 1+x


The Taylor seriesMathworldPlanetmath for  f⁢(x)=1+x  using the

T⁢(x)=∑k=0∞f(k)⁢(a)k!⁢(x-a)k

is given in the table below for the first few .


k
expansion simplified at  a=0
0 f⁢(a) (1+a)1/2 1
1 f′⁢(a)⁢(x-a) 12⁢(1+a)-1/2⁢(x-a) 12⁢x
2 f(2)⁢(a)2!⁢(x-a)2 -18⁢(1+a)-3/2⁢(x-a)2 -18⁢x2
3 f(3)⁢(a)3!⁢(x-a)3 348⁢(1+a)-5/2⁢(x-a)3 116⁢x3
4 f(4)⁢(a)4!⁢(x-a)4 -15384⁢(1+a)-7/2⁢(x-a)4 -5128⁢x4
5 f(5)⁢(a)5!⁢(x-a)5 1053840⁢(1+a)-9/2⁢(x-a)5 7256⁢x5
6 f(6)⁢(a)6!⁢(x-a)6 -94546080⁢(1+a)-11/2⁢(x-a)6 -211024⁢x6
Table 1: Taylor Series for f⁢(x)=1+x

The general coefficient of the expansion, for n≥2 is:

f(n)⁢(a)n! =(12n)⁢(1+a)12-n
=12⁢(-12)⁢(-32)⁢⋯⁢(12-(n-1))n⁢(n-1)⁢(n-2)⁢⋯⁢1 (1+a)-2⁢n-12
=12⁢(-12)n-1 1⋅3⁢⋯⁢(2⁢n-3)n⁢(n-1)⁢(n-2)⁢⋯⁢1 (1+a)-2⁢n-12
=(-1)n-12n⁢n!⁢(2⁢n-3)!(2⁢n-4)⁢(2⁢n-6)⁢⋯⁢2 (1+a)-2⁢n-12
=(-1)n-1⁢(2⁢n-3)!22⁢n-2⁢n!⁢(n-2)! (1+a)-2⁢n-12.
Title Taylor expansion of 1+x
Canonical name TaylorExpansionOfsqrt1x
Date of creation 2013-03-22 15:45:52
Last modified on 2013-03-22 15:45:52
Owner stevecheng (10074)
Last modified by stevecheng (10074)
Numerical id 11
Author stevecheng (10074)
Entry type Example
Classification msc 26A09
Related topic ExamplesOnHowToFindTaylorSeriesFromOtherKnownSeries