there exist additive functions which are not linear
Proof.
Let V be the infinite dimensional vector space ℝ over the
field ℚ. Since 1 and √2 are two independent vectors in V, we can extend the set {1,√2} to a basis E of V (notice that here the axiom of choice
is used).
Now we consider a linear function f:V→ℝ such that f(1)=1 while f(e)=0 for all e∈E∖{1}. This function is ℚ-linear (i.e. it is additive on ℝ) but it is not ℝ-linear because f(√2)=0≠√2f(1).
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Title | there exist additive functions which are not linear |
---|---|
Canonical name | ThereExistAdditiveFunctionsWhichAreNotLinear |
Date of creation | 2013-03-22 16:17:50 |
Last modified on | 2013-03-22 16:17:50 |
Owner | paolini (1187) |
Last modified by | paolini (1187) |
Numerical id | 5 |
Author | paolini (1187) |
Entry type | Example |
Classification | msc 15A04 |