example of Fermat’s last theorem
Fermat stated that for any the Diophantine equation![]()
has no solution in positive integers. For this follows from the following
Theorem 1.
has no solution in positive integers.
Proof.
Suppose we had a positive such that holds. We may assume . Then must be odd, and have opposite parity. Since is a primitive Pythagorean triple![]()
, we have
| (1) |
where , are coprime![]()
and have opposite parity. Since is a primitive Pythagorean triple, we have coprime , of opposite parity satisfying
| (2) |
From it follows that , which implies . Since is a square, each of is a square.
Setting , , leads to
| (3) |
where . Thus, equation 3 gives a solution where . Applying the above steps repeatedly would produce an infinite![]()
sequence
![]()
of positive integers, each of which was the sum of two fourth powers. But there cannot be infinitely many positive integers smaller than a given one; in particular this contradicts to the fact that there must exist a smallest for which (1) is solvable. So there are no solutions in positive integers for this equation.
∎
A consequence of the above theorem is that the area of a right triangle![]()
with integer sides is not a square; equivalently, a right triangle with rational sides has an area which is not the square of a rational.
| Title | example of Fermat’s last theorem |
|---|---|
| Canonical name | ExampleOfFermatsLastTheorem |
| Date of creation | 2013-03-22 14:09:51 |
| Last modified on | 2013-03-22 14:09:51 |
| Owner | Thomas Heye (1234) |
| Last modified by | Thomas Heye (1234) |
| Numerical id | 9 |
| Author | Thomas Heye (1234) |
| Entry type | Example |
| Classification | msc 11F80 |
| Classification | msc 14H52 |
| Classification | msc 11D41 |
| Related topic | InfiniteDescent |
| Related topic | X4Y4z2HasNoSolutionsInPositiveIntegers |