# places of holomorphic function

If $c$ is a complex constant and $f$ a holomorphic function  in a domain $D$ of $\mathbb{C}$, then $f$ has in every compact  (closed (http://planetmath.org/TopologyOfTheComplexPlane) and bounded   (http://planetmath.org/Bounded)) subdomain of $D$ at most a finite set  of http://planetmath.org/node/9084$c$-places, i.e. the points $z$ where  $f(z)=c$,  except when  $f(z)\equiv c$  in the whole $D$.

Proof.  Let $A$ be a subdomain of $D$.  Suppose that there is an infinite  amount of $c$-places of $f$ in $A$.  By http://planetmath.org/node/2125Bolzano–Weierstrass theorem, these $c$-places have an accumulation point  $z_{0}$, which belongs to the closed set  $A$.  Define the constant function $g$ such that

 $g(z)\;=\;c$

for all $z$ in $D$.  Then $g$ is holomorphic in the domain $D$ and  $g(z)=c$  in an infinite subset of $D$ with the accumulation point $z_{0}$.  Thus in the $c$-places of $f$ we have

 $g(z)\;=\;f(z).$

Consequently, the identity theorem of holomorphic functions implies that

 $f(z)\;=\;g(z)\;=\;c$

in the whole $D$.  Q.E.D.

Title places of holomorphic function PlacesOfHolomorphicFunction 2013-03-22 18:54:18 2013-03-22 18:54:18 pahio (2872) pahio (2872) 8 pahio (2872) Corollary msc 30A99 ZerosAndPolesOfRationalFunction IdentityTheorem TopologyOfTheComplexPlane