proof of Nakayama’s lemma

(This proof was taken from [1].)

If M were not zero, it would have a simple quotient, isomorphic to R/𝔪 for some maximal idealMathworldPlanetmath 𝔪 of R. Then we would have 𝔪MM, so that 𝔞MM as 𝔞𝔪.


  • 1 Serre, J.-P. Local Algebra. Springer-Verlag, 2000.
Title proof of Nakayama’s lemma
Canonical name ProofOfNakayamasLemma
Date of creation 2013-03-22 13:16:50
Last modified on 2013-03-22 13:16:50
Owner nerdy2 (62)
Last modified by nerdy2 (62)
Numerical id 6
Author nerdy2 (62)
Entry type Proof
Classification msc 13C99