sets where sequence of continuous functions diverge
Related Exercise from Rudin’s Real and Complex Analysis.
Replace “rational” by irrational in (a) and answer the resulting question.
Replace “ is unbounded” by “ as ” and answer the resulting analogues of (a) and (b).
Solution: The answer to (a) is negative. This by showing that the subset of points where such sequence is unbounded must be . But the rationals cannot be such, since in dense sets must be of second category.
Rest of the answer not yet ready here
|Title||sets where sequence of continuous functions diverge|
|Date of creation||2013-03-22 15:23:34|
|Last modified on||2013-03-22 15:23:34|
|Last modified by||yotam (10129)|