# tangents law

Let $ABC$ be a triangle with $a,b$ and $c$ being the sides opposite to $A,B$ and $C$ respectively. Then the following relation holds.

$$\frac{a-b}{a+b}=\frac{\mathrm{tan}(\frac{A-B}{2})}{\mathrm{tan}(\frac{A+B}{2})}.$$ |

Title | tangents law |
---|---|

Canonical name | TangentsLaw |

Date of creation | 2013-03-22 13:11:01 |

Last modified on | 2013-03-22 13:11:01 |

Owner | giri (919) |

Last modified by | giri (919) |

Numerical id | 5 |

Author | giri (919) |

Entry type | Theorem |

Classification | msc 51-00 |

Synonym | law of tangents |